**For the 3d part of his tutorial, Nasir, one of the members of the community, focused on losses in a transformer. Knowing that his last tutorial was about the Construction of a Transformer, what will you think about the following?**

An ideal transformer is the one which is 100% efficient. This means that the power supplied at the input terminal should be exactly equal to the power supplied at the output terminal, since efficiency can only be 100% if the output power is equal to the input power with zero energy losses. But in reality, nothing in this universe is ever ideal. Similarly, since the output power of a transformer is never exactly equal to the input power, due a number of electrical losses inside the core and windings of the transformer, so we never get to see a 100% efficient transformer.

Transformer is a static device, i.e. we do not get to see any movements in its parts, so no mechanical losses exist in the transformer and only electrical losses are observed. So there are two primary types of electrical losses in the transformer:

- Copper losses
- Iron losses

Other than these, some small amount of power losses in the form of ‘stray losses’ are also observed, which are produced due to the leakage of magnetic flux.

### Copper losses

These losses occur in the windings of the transformer when heat is dissipated due to the current passing through the windings and the internal resistance offered by the windings. So these are also known as ohmic losses or I2R losses, where ‘I’ is the current passing through the windings and R is the internal resistance of the windings.

These losses are present both in the primary and secondary windings of the transformer and depend upon the load attached across the secondary windings since the current varies with the variation in the load, so these are variable losses.

Mathematically, these copper losses can be defined as:

_{ohmic}= I

_{p}R

_{p}+ I

_{s}R

_{s}

Iron losses

There are two types of Iron losses in the transformer:

- Eddy Current losses
- Hysteresis Loss

#### Eddy Current Losses

When an alternating current is supplied to the primary windings of the transformer, it generates an alternating magnetic flux in the winding which is then induced in the secondary winding also through Faraday’s law of electromagnetic induction, and is then transferred to the externally connected load. During this process, the other conduction materials of which the core is composed of; also gets linked with this flux and an emf is induced.

But this magnetic flux does not contribute anything towards the externally connected load or the output power and is dissipated in the form of heat energy. So such losses are called Eddy Current losses and are mathematically expressed as:

_{e}= K

_{e}f² K

_{f}² B

_{m}²

Where;

- K
_{e}= Constant of Eddy Current - K
_{f}² = Form Constant - B
_{m}= Strength of Magnetic Field

#### Hysteresis Loss

**Hysteresis loss is defined as the electrical energy which is required to realign the domains of the ferromagnetic material which is present in the core of the transformer. **

These domains loose their alignment when an alternating current is supplied to the primary windings of the transformer and the emf is induced in the ferromagnetic material of the core which disturbs the alignment of the domains and afterwards they do not realign properly. For their proper realignment, some external energy supply, usually in the form of current is required. This extra energy is known as Hysteresis loss.

Mathematically, they can be defined as;

_{h}= K

_{h}B

_{m}

^{1.6}fV

Transformer has two states of operations, one is without load and the other is with load. Most of these errors appear when the load is applied on the transformer.

**So it is essential to read the behavior of transformer when load is applied on it, which we will see in the next post of this tutorial. Till then take care and leave me your impressions.**

Nasir.

It is very useful information, Thank you for your blog. But other than these losses, are there any other losses?

Hi Nasir, thank you for your valuable contribution to our learning path. Please take a look on the copper loss equation cause I think is missing the square on the currente value. Regards.

Thank you for share this information which is about transformer.

its awsmmmmmmm….

The formula on total copper losses should be

Pohmic = Ip2*Rp + Is2*Rs, heat desipated in time t seconds = Pohmic x t

IF WE INCREASE THE FREQUENCY E OF TRANSFORMER KEEPING WITH FIXED VOLTAGE THEN WHAT WILL EFFECT ON.

EDDY CURRENT WILL BE……?

HYSTERESIS LOSSES WILL BE…..?

it is best answer i have ever found thanksssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

very helpfull details

great informatio

Dear Sir,

you are requested to provide me the list of No load loss and full load loss of all the power and distribution transformers for all the voltage ratio or whatever available with you. I shall be really grateful for providing the same.

Pe=ke.V.f^2.t^2.Bm^2.

t=thickness of lamination..

V=volume of iron.

Other thing is same..this is from book so I have confusion that both are correct but what is the basic difference between this two..

are the iron losses directly proportional to voltage or are the losses exponential as is the case with copper losses

Hi,

What is winding loss? is it same as copper loss?

Thanks,

Nazu

differentiate between iron and copper losses

Thanks and well done Nasir these information is good it gave me an immediate answer to my assignment

GOODJOB