Leynin

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  • in reply to: KW Calculation #11578
    Leynin
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    There will naturally be a decrease in the value of voltage at your load terminals due to I²R loss (heat) plus reactive drops if electric motors are connected. Determine the supply current from

     

                         I = 35 X 10³ ⁄ (I x V x cosΦ√3

    and the total impedance of the circuit from the source to the load, ie, the R of a 35m length cable (what is the csa? and is it made of CU?) + the impedance of the connected appliances. There is a standard allowable voltage drop(mV/A/m) for your particular cable, not more than 4% of your supply voltage (IEEE). Check this and use the formula,

     

                         Total voltage drop = (mV/A/m) x I x 35 / 1000

    That will be the value at the load terminals.

    In 2004 in the United States, there were 104 (69 pressurized water reactors and 35 boiling water reactors)
    commercial nuclear generating units licensed to operate, producing a
    total of 97,400 megawatts (electric), which is approximately 20% of the
    nation’s total electric energy consumption
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