Here's a question for all you engineers out there. Let us suppose you have a transformer with the secondary short circuited i.e. full load. Instead of applying a small voltage as you would in a short circuit test we apply the rated voltage instead. What would be the primary current? I would of thought of just applying the basic formula of rated Voltage-Amperes divided by rated Voltage equals Current flow of the primary. But I could be wrong. It's pretty clear that the secondary current would be very high but what about the primary? Would the turns ratio apply in this situation too?