Home › Electrical Engineering Forum › General Discussion › REACTIVE POWER
- This topic has 5 replies, 5 voices, and was last updated 14 years, 10 months ago by
Spir Georges GHALI.
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- 2010/12/17 at 6:22 am #10310
admin
KeymasterWHY REACTIVE POWER IS RETURNED TO SOURCE
2011/04/30 at 3:07 pm #12030admin
KeymasterBecause The vector of current is leading the vector of voltage. Your load is capacitive
2011/05/01 at 7:39 pm #12037Nawaz
ParticipantThis can be viewed from other term too. As we know the average power consumed by a inductor or a capacitor over a complete cycle is zero.During the first half cycle a field builds up across the inductor and during the second half cycle the field collapses. So power has to be returned back to source
2011/05/03 at 12:30 pm #12041silver lining
ParticipantDoes reactive power return from the same path where it cames from?
Can u please detail it.
2011/05/03 at 1:22 pm #12042electricalexpert65
ParticipantNawaz said:
This can be viewed from other term too. As we know the average power consumed by a inductor or a capacitor over a complete cycle is zero.During the first half cycle a field builds up across the inductor and during the second half cycle the field collapses. So power has to be returned back to source
A bit of correction! It is not between the two half cycles. Even in the same half cycle, the charge builds up from zero to maximum in the first half of the half cycle and then from the peak to zero of the same half cycle, the built-up charge would discharge back to the source. Again, in the next half cycle, the same process is repeated albeit in the reverse polarity.
2011/06/08 at 11:41 am #12158Spir Georges GHALI
ParticipantAbdul Jabbar said:
WHY REACTIVE POWER IS RETURNED TO SOURCE
Dear Mr. Abdul Jabbar ;
I thnik you are talking about the reactive power that we have from ” Capacitors Bank “.
First, we should know that the ” Capacitors ” are like other ” Loads ” installed on the network, so, as we have an ” Inductive Loads ” and a ” Resistive Loads “, we have also a ” Capacitive Loads “, so, the current of the capacitve loads will run to the source. But from the point of view of the source we have the ” Vectorial Sum ” of 3 currents that are ” Inductive, Capacitive, and Resistive currents “.
Regards.
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