- This topic has 7 replies, 2 voices, and was last updated 5 years, 5 months ago by Anonymous.
2013/06/11 at 3:48 pm #11020Steven MillParticipant
For the 3d part of his tutorial, Nasir, one of the members of the community, focused on losses in a transformer. Knowing that his last tutorial was about the Construction of a Transformer, what will you think about the following?
An ideal transformer is the one which is 100% efficient. This means that the power supplied at the input terminal should be exactly equal to the power supplied at the output terminal, since efficiency can only be 100% if the output power is equal to the input power with zero energy losses. But in reality, nothing in this universe is ever ideal. Similarly, since the output power of a transformer is never exactly equal to the input power, due a number of electrical losses inside the core and windings of the transformer, so we never get to see a 100% efficient transformer.
Transformer is a static device, i.e. we do not get to see any movements in its parts, so no mechanical losses exist in the transformer and only electrical losses are observed. So there are two primary types of electrical losses in the transformer:
- Copper losses
- Iron losses
Other than these, some small amount of power losses in the form of ‘stray losses’ are also observed, which are produced due to the leakage of magnetic flux.
These losses occur in the windings of the transformer when heat is dissipated due to the current passing through the windings and the internal resistance offered by the windings. So these are also known as ohmic losses or I2R losses, where ‘I’ is the current passing through the windings and R is the internal resistance of the windings.
These losses are present both in the primary and secondary windings of the transformer and depend upon the load attached across the secondary windings since the current varies with the variation in the load, so these are variable losses.
Mathematically, these copper losses can be defined as:
Pohmic = IpRp + IsRs
These losses occur in the core of the transformer and are generated due to the variations in the flux. These losses depend upon the magnetic properties of the materials which are present in the core, so they are also known as iron losses, as the core of the Transformer is made up of iron. And since they do not change like the load, so these losses are also constant.
There are two types of Iron losses in the transformer:
- Eddy Current losses
- Hysteresis Loss
Eddy Current Losses
When an alternating current is supplied to the primary windings of the transformer, it generates an alternating magnetic flux in the winding which is then induced in the secondary winding also through Faraday’s law of electromagnetic induction, and is then transferred to the externally connected load. During this process, the other conduction materials of which the core is composed of; also gets linked with this flux and an emf is induced.
But this magnetic flux does not contribute anything towards the externally connected load or the output power and is dissipated in the form of heat energy. So such losses are called Eddy Current losses and are mathematically expressed as:
Pe = Ke f² Kf² Bm²
- Ke = Constant of Eddy Current
- Kf² = Form Constant
- Bm = Strength of Magnetic Field
Hysteresis loss is defined as the electrical energy which is required to realign the domains of the ferromagnetic material which is present in the core of the transformer.
These domains loose their alignment when an alternating current is supplied to the primary windings of the transformer and the emf is induced in the ferromagnetic material of the core which disturbs the alignment of the domains and afterwards they do not realign properly. For their proper realignment, some external energy supply, usually in the form of current is required. This extra energy is known as Hysteresis loss.
Mathematically, they can be defined as;
>Ph = Kh Bm1.6 fV
These are the different kinds of losses happened to occur in transformer and an electrical engineer must take care of their losses and try to reduce them as low as possible.
Transformer has two states of operations, one is without load and the other is with load. Most of these errors appear when the load is applied on the transformer.
So it is essential to read the behavior of transformer when load is applied on it, which we will see in the next post of this tutorial. Till then take care and leave me your impressions.
Nasir.2013/06/13 at 9:53 am #13069AnonymousGuest
It is very useful information, Thank you for your blog. But other than these losses, are there any other losses?2013/06/28 at 1:41 pm #13304AnonymousGuest
Hi Nasir, thank you for your valuable contribution to our learning path. Please take a look on the copper loss equation cause I think is missing the square on the currente value. Regards.2014/05/27 at 3:17 pm #13458AnonymousGuest
Thank you for share this information which is about transformer.2015/10/15 at 10:13 pm #13731AnonymousGuest
So if im reading this right, hysteresis losses are due to the energy required to overcome the opposition of magnetism?? That right?2015/11/18 at 12:17 pm #13745AnonymousGuest
its awsmmmmmmm….2016/01/25 at 11:12 am #13753AnonymousGuest
The formula on total copper losses should be
Pohmic = Ip2*Rp + Is2*Rs, heat desipated in time t seconds = Pohmic x t2016/02/15 at 12:40 pm #13757AnonymousGuest
IF WE INCREASE THE FREQUENCY E OF TRANSFORMER KEEPING WITH FIXED VOLTAGE THEN WHAT WILL EFFECT ON.
EDDY CURRENT WILL BE……?
HYSTERESIS LOSSES WILL BE…..?
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