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A residential electric power consumer having 53kw installed and connected loads with overall power factor of 0.83 wishes to install an uniterupted power supply,static back up system that will be able to supply some critical loads for 8hours on daily basis.if the percentage of the critical load is 30% ot the connected load and assuming 75% efficiency of the back-up system.determine the capacity i.e ampere-hour,A-hr,of deep cycle cells required.
KVA =53/.83
critical load = kva * .30
back-up system = critical load/.75 in kva
divide by system voltage to get amps
multiply by 8 to get amphours
Emmanuel Chimezie Diogu said:
A residential electric power consumer having 53kw installed and connected loads with overall power factor of 0.83 wishes to install an uniterupted power supply,static back up system that will be able to supply some critical loads for 8hours on daily basis.if the percentage of the critical load is 30% ot the connected load and assuming 75% efficiency of the back-up system.determine the capacity i.e ampere-hour,A-hr,of deep cycle cells required.
Dear ;
Plus to that said by SJ, I want to draw your attention that there's another element to define finally the power of needed UPS, this element is the ” Creast Factor ” for these loads, because when the value of CF increase the power the UPS should be increased also.
Regards.
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