# Electrical installation & energy efficiency

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transformer losses
2011/04/26
10:03 am
amit kulkarni
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hi can u help me @ transformer (3 phase) losses any formulae or thumb rules.if the transformer is 50 % loaded there are some losses but how to calculate? how we to calculate % of transformer loading?

2011/05/26
12:21 pm
Anil Sabaji PE CEng
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Hi,

Look for Transformer Test report. It will have Iron losses which will remain almost constant through out the loading cycle. Then look for efficiency on the name plate. This corresponds to full load. Now calculate the full load losses. Example if 1000KVA transformer efficiency is 98% then the losses are 2% i.e. 20KW. If the Iron Losses is indicated as 2KW, then the copper losses are 18KW. Now the copper losses are proportional to square of current. Therefore at 50% load copperlosses will be 0.5 sqare times the full load copper loss. i.e. 0.25X18=4.5KW. Therefore at 50% load you will have 6.5KW losses. If you dont know what is the Iron losses of the transformer, then see the noload power consumption of the transformer, it will  be very close to iron losses.

2011/05/26
4:30 pm
kailash
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anil i agree with you.

But i think to know the full load losses you have to go for open ckt test (i.e. iron losses) and short ckt test (i.e copper losses).then to know tfransformer loss at any load= iron loss + copper loss at that load.

e.g.  copper loss at 50% load = ( 50% 0f full load current)2*R

=(I/2)2*R

=I2R/4

2011/05/27
4:04 am
Mohsan islam
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Forum Posts: 4
Member Since:
2011/05/14
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Transformer losses are found by short circuit test and open circuit test.

2011/05/28
11:48 am
mhrnaseer
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i want to calcute my home electricity load and also want to know illuminus calclations formuly any bdy hlp me plz?

2011/06/01
8:48 am
Spir Georges GHALI
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Forum Posts: 204
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2011/03/26
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amit kulkarni said:

hi can u help me @ transformer (3 phase) losses any formulae or thumb rules.if the transformer is 50 % loaded there are some losses but how to calculate? how we to calculate % of transformer loading?

Dear Amit ;

there are 2 kinds of losses : Iron Losse & Cupper losse, the iron loose is not affected by the load, but the cupper load si affected by the load.

Normally, on the name plate of any transformer there's a percentage value " i % " that's the percentage current of the nominal current for the iron losse, so, if we have it we can calculate the iron losse. and also on the name plate there is a value of cupper losse on full load in " watt ", by whici we can calculate the " R " of the transformer then accordingly the load's current and the value of R we can calculate the cupper losse, notint taht the formula by which we calculate the " R " of any transformer is : R = Pcu/3 . In2  ; where :

- Pcu : is the full load cupper losse

- In2 : is the square on the transformer nominal current

Regards.

2011/06/04
11:14 am
Mohsan islam
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Forum Posts: 4
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2011/05/14
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i want

to calcute my home electricity load and also want to know illuminus calclations

formuly any bdy hlp me plz?

Hello Dear mhrnaseer,

ammeter.

Multiply load current to standard voltages which are usually

Illumination is defined as “the emitted luminous flux per

unit area is called illumination”.

Mathematically

E=Φ/A    (lux).

Illumination at any surface can be calculated by two laws:

1) inverse square law

2) Lambert’s law

1)inverse square law tells that the illumination of a

surface is inversely proportional to the square

of  the distance of the surface

from the source.

i.e   E «1/d^2

2) Lambert’s law tells that illumination is directly

proportional to cosine of the angle made by the normal to the illuminated

surface with the direction of the incident flux.

i.e E  « I cosΘ   where I is  luminous intensity.

combining the both laws we get

E «(I/d^2)cosΘ

Or

E=(I/d^2)cosΘ

2011/06/11
1:44 am
akhila....
Guest

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amit kulkarni said:

hi can u help me @ transformer (3 phase) losses any formulae or thumb rules.if the transformer is 50 % loaded there are some losses but how to calculate? how we to calculate % of transformer loading?

W(cu,xfl)=X*X*W(cu,fl)    where W(cu,fl) is the full load copper loss……                                                                                                              and the total transformer loss will be iron loss+copper loss

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